wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation (cos p - 1)x2 + (cos p)x + sin p = 0 in variable x has real roots, if p belongs to the interval


A

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D


(cos p - 1)x2 + (cos p)x + sin p = 0 .....(1)

Discriminant of (1) is given by D = cos2 p - 4 (cos p - 1)sin p = cos2 p + 4 (1 - cos p) sin p

Note that cos2 p0,1 cos p0. Thus, D0 if sin p0 i.e if pϵ(0,π)


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving Trigonometric Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon