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Question

The equation 3cos1xπxπ2=0 has

A
one negative solution
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B
one positive solution
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C
no solution
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D
more than one solution
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Solution

The correct option is C one positive solution
Substituting x=12 , we get
3cos1(12)π2π2
=3(π3)π
=0
Hence there is one positive real solution to the above equation since range of cos1(x)ϵ[π,0].

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