Question

The equation, $\alpha =\frac{D-d}{(n-1)d}$ is correct matched for :

• A. $A\rightleftharpoons nB/2+nC/3$
• B. $A\rightleftharpoons nB/2+\left(2n/3\right)C$
• C. $A\to \left(n/2\right)B+\left(n/4\right)C$
• D. $A\rightleftharpoons \left(n/2\right)B+C$

Answer 1

The correct option is B $A\rightleftharpoons nB/2+\left(2n/3\right)C$

In the above equation of degree of dissociation(a), n denotes the number of molecules formed in product side per mole of the reactant side.
In A, $\frac{5n}{6}$ moles are formed, $\frac{3n}{4}$ in C and $\frac{n}{2}+1$ in D.
Only B results in formation of n moles.