The equation |¯r|2−¯r⋅(2^i+4^j+4^k)−16=0 represent a
A
a circle
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B
a sphere of radius 3 units
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C
a plane
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D
a sphere of radius 5 units
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Solution
The correct option is D a sphere of radius 5 units |¯r|2−¯r(2i+4j+4k)−16=0 |¯r|2−2¯r(i+2j+2k)+|i2+(2j)2+(2k)2|−9−16=0 (¯r−(i+2j+2k))2=25 Clearly this is equation of a sphere with PV i+2j+2k and radius 5.