The equation ∫π/4−π/4(λ|sinx|+μsinx1+cosx+v)dx=0,whereλ,μ,v are constants,
gives a relation between ?
A
λ,μ and v
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B
λ and v
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C
λ,μ
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D
μ and v
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Solution
The correct option is Cλ and v ∫π4−π4(λ|sinx|+μsinx1+cosx+v)dx =∫π4−π4|sinx|+μ∫π4−π4sinx1+cosxdx+v∫π4−π4dx =−λ∫0−π4sinxdx+λ∫π40sinx+μ∫π4−π4sinx1+cosxdx+v∫π4−π4dx =−λ[−cosx]0−π4+λ[−cosx]π40+μ[−log(1+cosx)]π4−π4+v[x]π4−π4 =−λ(−1+1√2)+λ(−1√2+1) +μ[−log(1+1√2)+log(1+1√2)]+v[π4+π4] =2λ+vπ2