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B
one root
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C
two root
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D
infinite roots
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Solution
The correct option is D infinite roots sin2θ−4sin3θ−1=1−4sin3θ−1 = sin2θ=1 = sinθ=±1 But sinθ≠1 Thus, sinθ=−1 θ=3π2,7π2... hence, the equation has infinite solutions.