Question

The equation $e^x=m(m+1),m<0$ has

• A. no real root
• B. exactly one real root
• C. two real root
• D. none of these

Answer 1

The correct option is D none of these

$e^x=m(m+1)$
Taking $\log$ on both sides,
$x=\log \left(m\right(m+1\left)\right)$
From this, we get $m(m+1)>0\Rightarrow m\in (-\infty ,-1)\cup (0,\infty )$
But, $m<$, (given)
$\therefore m<-1$
From Graph, we can see that there are infinite no. of real values of x...