The equation for kinetic energy is- KE - 1-2 mv2-What is the correct equation when this equation is solved for mass-

The correct option is D m = 2 (KE)v^2 Kinetic energy #160; #160; #160; KE = 12mv^2 #160; #160; #160; m = 2(KE)v^2 ...

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Byju's Answer

Standard XII

Physics

Newton's Laws for System of Particles

The equation ...

Question

The equation for kinetic energy is: $K E = \frac{1}{2} m v^{2}$ .
What is the correct equation when this equation is solved for mass?

m = \frac{1}{2} m (K E)^{2}

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m = (\frac{2 (K E)}{v})^{2}

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m = \sqrt{\frac{2 (K E)}{v}}

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m = \frac{2 (K E)}{v^{2}}

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m = \frac{2 (K E)^{2}}{v}

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Solution

The correct option is D $m = \frac{2 (K E)}{v^{2}}$
Kinetic energy $K E = \frac{1}{2} m v^{2}$

$⟹$ $m = \frac{2 (K E)}{v^{2}}$

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Similar questions

Q. E=mc^2 or, m=E/c^2
KE=1/2mv^2 or, m=2KE/v^2
2KE/v^2=E/c^2
When v=c then 2KE=E
So, can we say that the kinetic energy of a body is half of the energy when it travels at the speed of light?

Q. What is kinetic energy? Derive an equation for the kinetic energy of a body of mass '

m

' moving at a speed '

v

Q. The kinetic energy possessed by a body of mass

m

, moving with a velocity

v

is equal to

\frac{1}{2} m v^{2}

, provided:

According to pressure equation, PV=1/3 M Vrms².

=>nRT=1/3 M Vrms²

=> T directly proportional to M Vrms²

According to mean Kinetic energy,

KE(avg)=1/2 M Vrms²

=> KE(avg) directly proportional to M Vrms²

This means.. M Vrms² directly proportional to KE(avg) T

=> M Vrms² /T = KE(avg) × proportionality constant

So this means the avg Kinetic energy is inversely proportional to Absolute Temperature. But actually KE(avg) is directly proportional to T. Please clear my doubt

Q. A boy recalls the relation almost correctly but forgets where to put the constant

c

i.e. speed of light. He writes

m = \frac{m_{0}}{\sqrt{1 - v^{2}}}

, where

m

and

m_{0}

stand for masses and

v

for speed. Right place of

c

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The equation for kinetic energy is: KE=12mv2.What is the correct equation when this equation is solved for mass?

The correct option is D m=2(KE)v2Kinetic energy KE=12mv2⟹ m=2(KE)v2

The equation for kinetic energy is: $K E = \frac{1}{2} m v^{2}$ .
What is the correct equation when this equation is solved for mass?

The correct option is D $m = \frac{2 (K E)}{v^{2}}$
Kinetic energy $K E = \frac{1}{2} m v^{2}$

$⟹$ $m = \frac{2 (K E)}{v^{2}}$