Question 12

The equation having 5 as a solution is

(a) 4x + 1 = 2

(b) 3 - x = 8

(c) x - 5 = 3

(d) 3 + x = 8

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Solution

Let us solve the equations:
(a) Given equation is 4x + 1 = 2
$\Rightarrow 4 x = 2 - 1 \Rightarrow 4 x = 1 \Rightarrow x = \frac{1}{4}$
(b) Given equation is 3 - x = 8
$\Rightarrow - x = 8 - 3 \Rightarrow - x = 5 \Rightarrow x = - 5$
(c) Given equation is x - 5 = 3
$\Rightarrow x = 3 + 5 \Rightarrow x = 8$
(d) Given equation is 3 + x = 8
$\Rightarrow x = 8 - 3 \Rightarrow x = 5$

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Question 13

The equation having -3 as the solution is

(a) x + 3 = 1

(b) 8 + 2x = 3

(d) 2x + 1 = 3

y - x = 1

x = y^{2}

s i n^{- 1} \frac{2}{3} x + s i n^{- 1} \frac{\sqrt{5}}{3} x = s i n^{- 1} x

{log}_{3} (3 x - 8) = 2 - x,

x

If the pair of linear equations $k x - y = 5, x + k y = 5$ has a unique solution $(x = 2, y = 1)$ , then the value of k is ____.

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