The equation k2x2+kx+1=0 has :
no real roots
Comparing the given the quadratic equation with the standard form, we get
a = k2, b = k, c = 1
We know that D=b2−4ac
⇒(k)2−4(k2)(1)
⇒k2−4k2
⇒−3k2<0
Regardless of the value of k, −3k2 will be negative and since the discriminant is less than zero, the equation has no real roots.