The correct options are
A exactly three real solutions
B at least one real solutions
C exactly one irrational solution
x[(log5x)2−(9/2)log5x+5]=5√5 is valid when x>0
Taking logarithms with base 5 on both the sides, we get
[(log5x)2−92log5x+5]log5x=32[∵logam=mloga&logaa=1]
⇒2(log5x)3−9(log5x)2+10log5x−3=0
⇒(log5x−1)(log5x−3)(2log5x−1)=0
⇒log5x=1,log5x=3,2log5x=1
⇒x=5,125,√5
Ans: A,B,C