The equation ${(x^{2} - a^{2})}^{2} + {(y^{2} - b^{2})}^{2} = 0$ points

(\pm a, \pm b)

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(0, 0)

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(a, b)

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(b, a)

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Solution

The correct option is A $(\pm a, \pm b)$
The square terms are always positive or $0$
To give the sum as $0$
$x^{2} - a^{2} = 0 x^{2} = a^{2} x = \pm a$ or $y^{2} - b^{2} = 0 y^{2} = b^{2} y = \pm b$
So the points are $(\pm a, \pm b)$

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