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Question

The equation logex+loge(1+x)=0 can be written as

A
x2+xe=0
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B
x2+x1=0
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C
x2+x+1=0
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D
x2+xee=0
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Solution

The correct option is B x2+x1=0
logex+loge(1+x)=0
logex(1+x)=0
x(x+1)=0
x2+x=1
x2+x1=0

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