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Halogenation of Alpha Carbon

The equation ...

Question

The equation M+(x+y)NH3-->[M(NH3)x]⁺+[e(NH3)y]^- in this equation M is a alkali metal what is the meaning of x and y in the equation. I

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Solution

Here the x, y are meaning that there are total of x+y molecules of ammonia out of which x molecules are associating with metal to form the compound.
M + x NH3 --> [M(NH3)x]^+
and the rest y molecules of ammonia is combining with electrons released by sodium to form ammoniated electrons
yNH3 +e --> [e(NH3)y]^-
This are approximate values for ammonia combining with metal and electron because there is no fixed ratio in this reaction.

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Similar questions

In the reaction :

M + (x+y)NH₃ ____>_[M(NH3)x]+ _{+. [e(NH3)y]^-}

_{^{{Where M is alkali metal } what is the meaning of 'x' and 'y'?}}

Q. The alkali metals dissolve in ammonia to give a deep blue solution which is conducting in nature.

M + (x + y) N H_{3} \to [M (N H_{3})_{x}]^{2 +} + 2 [e (N H_{3}) y]^{-}

Which of the following is not true about the solutions are alkali metals in liquid ammonia?

Q. Alkali metals(M) dissolve in liquid

N H_{3}

Q. Consider the equation

y - y_{1} = m (x - x_{1})

. In this equation, if

m

x_{1}

are fixed and different lines are drawn for different values of

y_{1}

All alkali metals dissolve in anhydrous liquid ammonia to give a blue color solution. It is the ammoniated electron which is responsible for the blue color of the solution, and the electrical conductivity is due to ammoniated cation,

[M (N H_{3})_{x}]^{+}

as well as the ammoniated electron,

[e (N H_{3})_{y}]^{-}

, values of x and y depend on the extent of solvation by

N H_{3}

. Dilute solutions are paramagnetic due to free ammoniated electrons.

What happens if alkali metals are allowed to react with concentrated liquid ammonia?

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