The equation of a circle whose x-coordinate of the centre is 5 and radius is 4 units and also touches the x-axis, is
A
x2+y2−10x+8y+49=0
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B
x2+y2−10x−8y+25=0
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C
x2+y2+8x−10y+25=0
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D
x2+y2−16x−9y−25=0
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Solution
The correct option is Bx2+y2−10x−8y+25=0
The required equation of the circle whose x-coordinate of the centre is 5 and radius is 4 units also touches the x-axis is (x−5)2+(y−4)2=42 [Since radius is equal to the y-coordinate of the centre] ⇒x2−10x+25+y2−8y+16=16 ⇒x2+y2−10x−8y+25=0