The equation of a diameter of circle $x^{2} + y^{2} + 6 x + 2 y = 0$ passing through origin is

x + 3y = 0

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x - 3y = 0

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3x + y = 0

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3x - y = 0

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Solution

The correct option is A x + 3y = 0
Centre (3, –1). Line through it and origin is x + 3y = 0.

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Equation of the diameter of the circle $x^{2} + y^{2} - 2 x + 4 y = 0$ which passes through the origin is

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