Question

The equation of a hyperbola is given in its standard form as $16x^2-9y^2=144$.Coordinates of foci is

• A. $(0,\pm 1)$
• B. $(0,\pm 1,0)$
• C. $(\pm 5,0)$
• D. $(0,\pm 5)$

Answer 1

The correct option is D $(0,\pm 5)$

$Given:16x^2-9y^2=144Or,\frac{x^2}{9}-\frac{y^2}{16}=1Weknow,be=\sqrt{a^2+b^2}\because (b>a)Or,be=\sqrt{9+16}Or,be=\pm 5\therefore Fociiis(0,\pm 5)$

Option [D]