The equation of a line is 3 – 4y + 12 = 0.

Find the slope of the line and equation of ⊥ to the given line, which passes through the point of intersection of the lines – y + 2 = 0 & 3 + y – 10 = 0

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Solution

The correct option is E

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Similar questions

x + 2 y = 5

3 x + 7 y = 17

3 x + 4 y = 14

x + 2 y = 5

3 x + 7 y = 17

3 x + 4 y = 10

x - y = 1

2 x - 3 y + 1 = 0

3 x + 4 y = 14

The equation of a line is 3x + 4y – 7 = 0. Find :

(i) the slope of the line

(ii) the equation of a line perpendicular to the given line and passing through the intersection of the lines x – y + 2 = 0 and 3x + y -10 = 0.

Find the equation of the line passing through the points (2, 3) and the point of intersection of the lines $4 x - 3 y = 7$ and $3 x + 4 y + 1 = 0$ .

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