The equation of a line parallel to $2 x - 3 y = 4$ which makes with the axes a triangle of area $12$ units is

3 x + 2 y = 12

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2 x - 3 y = 12

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2 x - 3 y = 6

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3 x - 2 y = 6

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Solution

The correct option is B $2 x - 3 y = 12$

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Similar questions

\frac{1}{2 (2 x + 3 y)} + \frac{12}{7 (3 x - 2 y)} = \frac{1}{2}

\frac{7}{2 x + 3 y} + \frac{4}{3 x - 2 y} = 2

2 x + 3 y \neq 0

3 x - 2 y \neq 0

\frac{1}{2 (2 x + 3 y)} + \frac{12}{7 (3 x - 2 y)} = \frac{1}{2}, \frac{7}{(2 x + 3 y)} + \frac{4}{(3 x - 2 y)} = 2

(2 x + 3 y)

\frac{4}{3} x + 2 y = 8

2 x + 3 y = 12

The equation of a straight line passing through the origin and perpendicular to the straight line 2x + 3y - 7 = 0 is ______.

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