The equation of a line parallel to the y- axis and passing through (-3, -2) is _____.

x - 3 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x + 3 =0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

y + 2 =0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

y - 2 =0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B x + 3 =0
The equation of the line parallel to the y- axis is x = a; where a is the point where the line meets the x- axis. It is given that the line passes through the point (-3, -2).

$∴$ equation of line is x = -3 or x + 3 = 0 [i.e the x coordinate of the given point (-3, -2)]

Suggest Corrections

Similar questions

The equation of a straight line passing through the origin and perpendicular to the straight line 2x + 3y - 7 = 0 is ______.

Find the equation of the line parallel to the line $3 x + 2 y = 8$ and passing through the point $(0, 1)$ .

3 x - 4 y + 2 = 0

(- 2, 3)

Join BYJU'S Learning Program