The equation of a line which is parallel to line 2x = 3y - 4 and meets the y-axis at (0, 4) is .

3 y = 2 x + 12

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3 y = 2 x - 12

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2 y = 3 x + 12

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Solution

The correct option is A $3 y = 2 x + 12$
Given,
Equation of the line:
$2 x = 3 y - 4$
$3 y = 2 x + 4$
Slope, m = $\frac{2}{3}$

Since, $m_{1} = m_{2}$ [Parallel line]
$m_{2} = \frac{2}{3}$
Equation of a line passing through
(0, 4)

$(y - 4) = \frac{2}{3} \times (x - 0)$
$(y - 4) = \frac{2}{3} \times x$
$3 \times (y - 4) = 2 \times x$
$3 y - 12 = 2 \times x$
$3 y = 2 x + 12$

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