The equation of a parabola is y2=4x. Let P (1,3) and Q (1,1) are two points in the xyplane. Then,
A
P and Q are exterior points
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B
P is an interior point while Q is an exterior point
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C
P and Q are interior points
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D
P is an exterior point while Q is an interior point
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Solution
The correct option is DP is an exterior point while Q is an interior point Here, S≡y2−4x=0 S(1,3)=32−4.1>0 ⇒(1,3)isanexteriorpoint.Forthepoint(1,1),S(1,1)=11−4.1<0 ⇒Q(1,1) is an interior point