The equation of a plane passing through (1, 2, –3), (0, 0, 0) and perpendicular to the plane 3x – 5y + 2z = 11, is :
A
3x+y+53z=0
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B
4x + y + 2z = 0
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C
3x−y+z3=0
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D
x + y + z = 0
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Solution
The correct option is D x + y + z = 0 Equation of plane through (0, 0, 0) is ax + by + cz = 0 . . . .(1) (1) passes through (1, 2, –3) and ⊥ to the plane 3x – 5y + 2z = 11 ∴ a + 2b – 3c = 0 . . . .(2) ∴ 3a – 5b + 2c = 0 . . . .(3) ⇒a−11=b−11=c−11 ⇒a=b=c Hence, equation of required plane is x + y + z = 0.