The equation of a plane which cuts equal intercepts of unit length on the axes is

x + y + z = 0

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x + y + z = 1

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x + y - z = 1

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$\frac{x}{a} + \frac{y}{a} + \frac{z}{a} = 1$

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Solution

The correct option is B $x + y + z = 1$
The equation of the plane with intercepts $a, b, c$ on the axes is,
$\frac{x}{a} + \frac{y}{b} + \frac{z}{c}$ $= 1$
Since, $a, b, c = 1$ ,
$x + y + z = 1$

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The equation of a plane which cuts equal intercepts of unit length on the axes is

The correct option is B x+y+z=1The equation of the plane with intercepts a,b,c on the axes is,xa+yb+zc =1Since, a,b,c=1, x+y+z=1

The correct option is B $x + y + z = 1$
The equation of the plane with intercepts $a, b, c$ on the axes is,
$\frac{x}{a} + \frac{y}{b} + \frac{z}{c}$ $= 1$
Since, $a, b, c = 1$ ,
$x + y + z = 1$