The equation of a progressive wave is y=0.05sin(200t−x2)where x,y are in metres and t in seconds, then
a ) velocity of wave is 100ms−1
b) maximum velocity of particle in the wave is 10ms−1 c) wavelength of wave is 4πm
A
only a and c are true
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B
only b and c are true
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C
only a and b are true
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D
a,b,c are true
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Solution
The correct option is C only b and c are true particle velocity v=dydx=200×0.05cos(200t−x2) =10cos(200t−x2) ∴ maximum value is 10ms−1 k=2πλ=12⇒λ=4π Velocity of wave =wk=20012=400ms−1