The equation of a progressive wave where $t$ is the time in second $x$ is the distance in meter is $y = A c o s 240 (t - x / 12)$ . The phase difference (in Sl unit) between two positions $0.5 m$ apart is

40

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Solution

The correct option is C $10$
$y = A cos 240 (240 t - 240 \times 112)$
To find the wavelength $0.5 / λ = ϕ / 2 x$
$k = 240 / 12 = 20$ $0.5 / (2 π / 120) = ϕ / 2 x$
$k$ is a wave number
$λ = 2 x / 20$ $ϕ = 10 d e g r e e$
$λ$ is the wavelength.

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The equation of a progressive wave where t is the time in second x is the distance in meter is y=Acos240(t−x/12). The phase difference (in Sl unit) between two positions 0.5m apart is

The correct option is C 10y=Acos240(240t−240×112)To find the wavelength 0.5/λ=ϕ/2xk=240/12=20 0.5/(2π/120)=ϕ/2xk is a wave number λ=2x/20 ϕ=10degreeλ is the wavelength.

The equation of a progressive wave where $t$ is the time in second $x$ is the distance in meter is $y = A c o s 240 (t - x / 12)$ . The phase difference (in Sl unit) between two positions $0.5 m$ apart is

The correct option is C $10$
$y = A cos 240 (240 t - 240 \times 112)$
To find the wavelength $0.5 / λ = ϕ / 2 x$
$k = 240 / 12 = 20$ $0.5 / (2 π / 120) = ϕ / 2 x$
$k$ is a wave number
$λ = 2 x / 20$ $ϕ = 10 d e g r e e$
$λ$ is the wavelength.