The equation of a simple harmonic progressive wave is given by
y = 8sin (0.628x – 12.56t)
where x and y are in cm and t is in second.
Find the phase difference in degrees between two particles at a distance of 2.0cm apart at any instant.
72
y=a sin(ωt−kx)
The given equation is y=8sin(0.628x−12.56t)
Comparing, we get
a=8cm→ amplitude
k=0.628rad m−12πλ=0.628λ=2π0.628=10 cmω=12.56 rad s−12πf=12.56f=12.562π=2Hzv=fλ=2×10=20cms−1
Phase difference =Δϕ=2πλ× path difference
Δϕ=2π10×2=2π5=72∘