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Question

The equation of a simple harmonic progressive wave is given by
y = 8sin (0.628x – 12.56t)
where x and y are in cm and t is in second.
Find the phase difference in degrees between two particles at a distance of 2.0cm apart at any instant.


A

72

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B

64

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C

57

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D

45

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Solution

The correct option is A

72


y=a sin(ωtkx)
The given equation is y=8sin(0.628x12.56t)
​Comparing, we get
a=8cm amplitude
k=0.628rad m12πλ=0.628λ=2π0.628=10 cmω=12.56 rad s12πf=12.56f=12.562π=2Hzv=fλ=2×10=20cms1
Phase difference =Δϕ=2πλ× path difference
Δϕ=2π10×2=2π5=72


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