CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation of a stationary wave is y=0.8cos (πx20)sin200πt, where x is in cm and t is in seconds. The separation between a successive node and antinode will be

A
20 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10 cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
40 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
30 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 10 cm
For the stationary wave given by equation,
y=0.8cos(πx20)sin(200πt)
Comparing it with, y=2A cos kx sin ωt
We get, k=π20 & ω=200π
Wavelength of constituent waves is:
λ=2πk=2π(π20)=40 cm
The distance between a node & consecutive antinode is
Δx=λ4=404=10 cm

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon