Question

The equation of a straight line passing through $(-3,2)$ and cutting an intercept equal in magnitude but opposite in sing from the axes is given by

• A. $x-y+5=0$
• B. $x+y-5=0$
• C. $x-y-5=0$
• D. $x+y+5=0$

Answer 1

The correct option is C $x-y-5=0$

Solution:

Let equation be $\frac{x}{t}+\frac{y}{-t}=1$

It passes through $(-3,2)$

$\therefore \frac{-3}{t}-\frac{2}{t}=1$

$\Rightarrow t=-5$

Now Subs. we get

$\frac{x}{-5}+\frac{y}{5}=1$

$\Rightarrow -x+y=-5\Rightarrow x-y-5=0$