CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation of a straight line passing through a point (5,4) and which cuts off an intercept of 2 units between the lines x+y+1=0 and x+y1=0 is

A
x2y13=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2xy+14=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
xy+9=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
xy+10=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C xy+9=0

Let the given point be A=(5,4) and the given lines be l1x+y+1=0 and l2x+y1=0

The point A lies on l1


If segment AMl2 and M lies on l2, then, the distance AM is given by,


AM=|5+41|12+12=22=2


This means that if B is any point on l2 then AB>AM. No line other than AM cuts off an intercept of

length 2 between l1 and l2.


To determine the equation of AM, we need to find the co-ordinates of the Point M


Since, AMl2 and the slope l2 is 1, the slope ofAM must be 1. Also A(5,4) lies on AM


By the point slope formula, the equation of the required line is


y4=1(x(5))

y4=x+5

xy+9=0


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Area
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon