The equation of a straight line passing through the origin and perpendicular to the straight line 2x +3y -7 = 0 is

2y +3x = 0

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3y +2x = 0

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2y - 3x = 0

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None of these

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Solution

The correct option is A
2y +3x = 0

Let the equation of the line be ax +by + c = 0

Slope = $- (\frac{c o - e f f i c i e n t o f x}{c o - e f f i c i e n t o f y})$

Since, line is passing through origin, put (0, 0) in the equation

0+ 0+c = 0

So, c = 0

Slope of straight line 2x +3y -7 = 0

Slope = $- (\frac{c o - e f f i c i e n t o f x}{c o - e f f i c i e n t o f y})$

Slope of line given in question is – (2/3)

Hence, required line is y + (3/2) x = 0

Suggest Corrections

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