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Question

The equation of a straight line passing through the point (1,2) and inclined at 45 to the line y=2x+1 is

A
5x+y=7
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B
3x+y=5
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C
x+y=3
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D
xy+1=0
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Solution

The correct option is B 3x+y=5
Let y=mx+c be the equation then,
we know that when angle between two line is θ, then
tanθ=m1m21+m1m2
tan45°=m21+m2
m2=2m+1
m=3
y=3x+c passes through (1,2)
c=2+3=5
y+3x=5 is the equation.

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