wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation of a straight line passing through the point (1,2) and inclined at 45 to the line y=2x+1 is

A
5x+y=7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3x+y=5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
x+y=3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
xy+1=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 3x+y=5
Let y=mx+c be the equation then,
we know that when angle between two line is θ, then
tanθ=m1m21+m1m2
tan45°=m21+m2
m2=2m+1
m=3
y=3x+c passes through (1,2)
c=2+3=5
y+3x=5 is the equation.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon