The equation of a tangent to the hyperbola 4x2−5y2=20 parallel to the line x−y=2 is :
A
x−y+1=0
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B
x−y+7=0
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C
x−y−3=0
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D
x−y+9=0
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Solution
The correct option is Ax−y+1=0 The tangent to the hyperbola x25−y24=1 is y=mx±√5m2−4 The tangent is parallel to the line x−y=2 therefore, they have same slope. ⇒m=1 Hence, y=x±√5−4 y=x±1 ⇒y=x+1 or y=x−1 x−y+1=0 and x−y−1=0