The equation of a tangent to the hyperbola x2−2y2=18, which is perpendicular to the line x−y=0, is :
A
x+y=3
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B
x+y+2=0
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C
x+y=3√2
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D
x+y+3√2=0
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Solution
The correct option is Bx+y=3 Equation of line perpendicular to x−y=0 is given by y=−x+c Also this line is tangent to the hyperbola x2−2y2=18 So we have m=−1,a2=18,b2=9 Thus Using condition of tangency c2=a2m2−b2=18−9=9⇒c=±3 Hence required equation of tangent is x+y=±3