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Question

The equation of a tangent to the hyperbola x2−2y2=18, which is perpendicular to the line x−y=0, is :

A
x+y=3
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B
x+y+2=0
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C
x+y=32
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D
x+y+32=0
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Solution

The correct option is B x+y=3
Equation of line perpendicular to xy=0 is given by
y=x+c
Also this line is tangent to the hyperbola x22y2=18
So we have m=1,a2=18,b2=9
Thus Using condition of tangency c2=a2m2b2=189=9c=±3
Hence required equation of tangent is x+y=±3

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