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Question

The equation of a transverse wave is given by y=0.05sinπ(2t0.02x), where x, y are in metre and t is in second. The minimum distance of separation between two particles which are in phase and the wave velocity are respectively __________.

A
50m,50ms1
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B
100m,100ms1
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C
50m,100ms1
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D
100m,50ms1
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Solution

The correct option is C 100m,100ms1
The equation of given transverse wave is y=0.05sinπ(2t0.02x) .......(1)
On comparing (1) with y=Asin(wtkx)
We get, k=0.02π and w=2π
Wave velocity v=wk=2π0.02π=100 m/s
Minimum distance of separation between two particles which are in phase is equal to the wavelength of the wave.
Wavelength λ=2πk=2π0.02π=100 m

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