The equation of a transverse wave is given by y=0.05sinπ(2t−0.02x), where x, y are in metre and t is in second. The minimum distance of separation between two particles which are in phase and the wave velocity are respectively __________.
A
50m,50ms−1
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B
100m,100ms−1
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C
50m,100ms−1
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D
100m,50ms−1
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Solution
The correct option is C100m,100ms−1 The equation of given transverse wave is y=0.05sinπ(2t−0.02x) .......(1)
On comparing (1) with y=Asin(wt−kx)
We get, k=0.02π and w=2π
Wave velocity v=wk=2π0.02π=100m/s
Minimum distance of separation between two particles which are in phase is equal to the wavelength of the wave.