The equation of a transverse wave travelling on a rope is given by $y = 10 s i n π (0.001 x - 2.00 t)$ where y and x are in centimeters and t in seconds. The maximum transverse speed of a particle in the rope is about.

63 cm/s

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75 cm/s

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100 cm/s

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121 cm/s

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Solution

The correct option is A
63 cm/s

Standard equation of travelling wave $y = A s i n (k x - ω t)$ By comparing with the given equation

$y = 10 s i n (0.01 π x - 2 π t)$

$A = 10 c m, ω = 2 π$

Maximum particle velocity $= A ω = 2 π \times 10 = 63 c m / s$

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The equation of a transverse wave travelling on a rope is given by y=10sin π(0.001x−2.00t) where y and x are in centimeters and t in seconds. The maximum transverse speed of a particle in the rope is about.

The correct option is A 63 cm/s Standard equation of travelling wave y=A sin(kx−ωt) By comparing with the given equation y=10sin(0.01πx−2πt) A=10cm,ω=2π Maximum particle velocity =Aω=2π×10=63 cm/s

The equation of a transverse wave travelling on a rope is given by $y = 10 s i n π (0.001 x - 2.00 t)$ where y and x are in centimeters and t in seconds. The maximum transverse speed of a particle in the rope is about.

The correct option is A
63 cm/s

Standard equation of travelling wave $y = A s i n (k x - ω t)$ By comparing with the given equation

$y = 10 s i n (0.01 π x - 2 π t)$

$A = 10 c m, ω = 2 π$

Maximum particle velocity $= A ω = 2 π \times 10 = 63 c m / s$