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Byju's Answer
Standard XII
Physics
Velocity Displacement Relationship
The equation ...
Question
The equation of a wave propagating along a stretched string is given by
Y
=
4
sin
2
π
[
(
t
/
0.02
)
−
(
x
/
100
)
]
, where
Y
and
x
are in cm and
t
in second.
Determine maximum particle velocity.
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Solution
Given,
ω
=
2
π
0.02
=
100
π
Amplitude=4 cm
Max particle velocity=
A
ω
=
400
π
c
m
=
4
π
m
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