The equation of a wave travelling on a string stretched along -axis is given by y - Ae -x-a- t - T 2 Where is the maximum of pulse located at t - T -A- x-1-aB- x-1-aC- x-aD- x-a

The correct option is D x= a Maximum displacement y =A ⇒ A=Ae^ ( x/a+t/T )^2 For that to happen, x/a+ t/T=0 Now, substitute t=T⇒x/a= 1⇒ x= a ...

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Standard XII

Physics

Differential Equation of Wave

The equation ...

Question

The equation of a wave travelling on a string stretched along -axis is given by $(y = A e^{- {(\frac{x}{a} + \frac{t}{T})}^{2}})$
Where is the maximum of pulse located at t=T ?

$x = \frac{1}{a}$

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$x = \frac{- 1}{a}$

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$x = a$

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$x = - a$

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Solution

The correct option is D
$x = - a$

Maximum displacement y =A

$\Rightarrow A = A e^{- {(\frac{x}{a} + \frac{t}{T})}^{2}}$

For that to happen, $\frac{x}{a} + \frac{t}{T} = 0$

Now, substitute $t = T \Rightarrow \frac{x}{a} = - 1 \Rightarrow x = - a$

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The equation of a wave travelling on a string stretched along -axis is given by (y=Ae−(xa+tT)2) Where is the maximum of pulse located at t=T ?

The correct option is D x=−a Maximum displacement y =A ⇒A=Ae−(xa+tT)2 For that to happen, xa+tT=0 Now, substitute t=T⇒xa=−1⇒x=−a

The equation of a wave travelling on a string stretched along -axis is given by $(y = A e^{- {(\frac{x}{a} + \frac{t}{T})}^{2}})$
Where is the maximum of pulse located at t=T ?

The correct option is D
$x = - a$

Maximum displacement y =A

$\Rightarrow A = A e^{- {(\frac{x}{a} + \frac{t}{T})}^{2}}$

For that to happen, $\frac{x}{a} + \frac{t}{T} = 0$

Now, substitute $t = T \Rightarrow \frac{x}{a} = - 1 \Rightarrow x = - a$