Question

The equation of an alternating emf is $V=120\sin \left(100\pi t\right)\cos \left(100\pi t\right)$ Volt. The peak value of its emf and its frequency will be

Answer 1

$V=120\sin \left(100\pi t\right)\cos \left(100\pi t\right)=60\left[2\sin \right(100\pi t\left)\cos \right(100\pi t\left)\right]$

$⟹V=60\sin \left(200\pi t\right)$

Hence $V_{max}=60V$

$f=\frac{\omega }{2\pi }=100Hz$