wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation of chord joining 2 point P(α) and Q(β) in a hyperbola x2a2 y2b2= 1 is xa.cos (αβ2) yb.sin (α+β2) = cos [α+β2].


A

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

True


The points joined by the chord are Pa sec α,b tan α) and Q(a sec β,b tan β)

equation of chord is ,y b tan α = b.(tanαtanβ)a(secαsecβ).(x a sec α)

ay sec α ay sec β ab sec α.tan α + ab.secα.tan β

ay sec α ay sec β ab sec β.tan α

=bx.tanαbx.tanβ + ab secα tan β

Multiplying throughout by cosα.cosβab

yb.cosβyb.cosα+xa.cosα.sinβxa.cosβ.sinα

=sinβsinα

xa.sin(βα)+yb () 2.sin(α+β2).sin(αβ2)

=2.cosα+β2.sin[βα2]

xa.2sin(βα2)cos(βα2)yb.2sin(α+β2).sin(αβ2)

=2cosα+β2.sin(βα2)

Dividing by 2 sin (βα2)

xa.cos(βα2)yb.sinα+β2=cosα+β2

Hence the given statement is true


flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Lines and Points
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon