The equation of circle concentric with circle x2-y2-6 x-12 y-15-0 and double its area isA- x2-y2-6 x-12 y-15-0B- x2-y2-6 x-12 y-20-0C- x2-y2-6 x-12 y-45-0D- x2-y2-6 x-12 y-30-0

The correct option is A x 2+y2 6x+12y 15=0 x^2+y^2 6x+12y+15 = 0 C = (3, 6) ,r = (√(30)) (x 3)^2 + (y+6)^2 = 60 ⇒ x^2+y^2 6x+12y 15 = 0 ...

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General Equation of a Circle

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Question

The equation of circle concentric with circle $x^{2} + y^{2} - 6 x + 12 y + 15$ = 0 and double its area is

x²+y²-6x+12y-15=0

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x²+y²-6x+12y+20=0

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x²+y²-6x+12y+45=0

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x²+y²-6x+12y-30=0

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Similar questions

x^{2} + y^{2} - 6 x + 12 y + 15 = 0

x^{2} + y^{2} + 6 x + 6 y = 0

x^{2} + y^{2} - 12 x - 12 y = 0

Find the equation of the circle concentric with the circle
$x^{2} + y^{2} - 6 x + 12 y + 15 = 0$
and double of its area.

y^{2} = 4 x

x^{2} + y^{2} + 6 x - 12 y + 20 = 0

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