The equation of circle is $x^{2} + y^{2} - 2 x = 0$ . The point $P (- 1, 0)$ lies

On the circle

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Inside the circle

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Outside the circle

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On the centre of the circel

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Solution

The correct option is C Outside the circle
$x^{2} + y^{2} - 2 x = 0$ Radius $\Rightarrow (x - 1)^{2} + y^{2} = 1$
Radius $= 1$ center $(1, 0)$
$P t (- 1, 0) - (- 1)^{2} + 0 + 2 (- 1)$
$= 1 + 2 = 3$ (hence not on circle)
$O P = \sqrt{(- 1 + 1)^{2} + 0} = \sqrt{2}$ $O P >$ radius
$∴$ P will lie outside the circle

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The equation of circle is x2+y2−2x=0. The point P(−1,0) lies

The correct option is C Outside the circlex2+y2−2x=0 Radius ⇒(x−1)2+y2=1Radius =1 center (1,0)Pt(−1,0)−(−1)2+0+2(−1)=1+2=3 (hence not on circle)OP=√(−1+1)2+0=√2 OP> radius ∴ P will lie outside the circle

The equation of circle is $x^{2} + y^{2} - 2 x = 0$ . The point $P (- 1, 0)$ lies