Question

The equation of circle of radius $5$ and touching the coordinates axes in third quadrant, is

• A. $(x+5{)}^2+(y+5{)}^2=25$
• B. $(x-5{)}^2+(y-5{)}^2=25$
• C. $(x-5{)}^2+(y+5{)}^2=25$
• D. $(x+5{)}^2+(y-5{)}^2=25$

Answer 1

The correct option is A $(x+5{)}^2+(y+5{)}^2=25$

In third quadrant, both $x$ and $y$ co-ordinates will be negative,

Hence the co ordinates will be $-5$ and $-5$ as the circle touches both $x$ and $y$ axes,

Now the equation is

$(x-(-5){)}^2+(y-(-5){)}^2=5^2$.

$(x+5{)}^2+(y+5{)}^2=25$.

Hence, this is the answer.