The equation of circle whose diameter is the line joining the points (–4, 3) and (12, –1) is

x_{2} + (y_{2} + 8 x + 2 y + 51 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x_{2} + (y_{2} + 8 x - 2 y - 51 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x_{2} + (y_{2} + 8 x + 2 y - 51 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x_{2} + (y_{2} - 8 x - 2 y - 51 = 0.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $x_{2} + (y_{2} - 8 x - 2 y - 51 = 0.$
Required equation is
$(x - x_{1}) (x - x_{2}) + (y - y_{1}) (y - y_{2}) = 0$
$(x + 4) (x - 12) + (y - 3) (y + 1) = 0$
$x^{2} + y^{2} - 8 x - 2 y - 51 = 0.$

Suggest Corrections

Similar questions

(- 4, 3)

(12, - 1)

y - a x i s

(- 4, 3)

(12, - 1)

Find the equation of the circle whose diameter is the line segment joining (-4, 3) and (12, -1). Find also the intercept made by it on y-axis.

(1, - 3)

(2, 5)

Join BYJU'S Learning Program