The equation of circle with $(0, 0)$ as center and passing through $(4, 3)$

x^{2} + y^{2} = 5^{2}

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x^{2} + y^{2} = 10^{2}

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x^{2} + y^{2} = 7^{2}

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x^{2} + y^{2} = 1^{2}

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Solution

The correct option is A $x^{2} + y^{2} = 5^{2}$
The equation of circle with origin as center is $x^{2} + y^{2} = r^{2}$
$⟹ 4^{2} + 3^{2} = r^{2} r^{2} = 16 + 9 r^{2} = 25 r = 5$
.So the equation of circle is $x^{2} + y^{2} = 5^{2}$

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