The equation of circle with centre $(1, 1)$ and radius 4 is given by $(x - 1)^{2} + (y - 1)^{2} = 4$

True

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False

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Solution

The correct option is B
False

The centre of the circle is O $(1, 1)$ and radius is 4 units. Let us consider a general point P on the circle. Let the co-ordinates of the point P be $(x, y)$ .

$P O = 4$

$\Rightarrow \sqrt{(x - 1)^{2} + (y - 1)^{2}} = 4$

$\Rightarrow (x - 1)^{2} + (y - 1)^{2} = 16$ is the equation of the circle.

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