The equation of circum−circle of a ΔABC is x2+y2+3x+y−6=0.If A=(1,−2),B(−3,2) and the vertex C varies then the locus of ortho−centre of Δ ABC is a
Circle
Let c = (x,y,) and ortho centre = (x, y) since A, B and C are points on the circle we have centroid G=(∑x3,∑y3)(x,y)=(x1−2,y1)
⇒(x,y1)=(x+2,y) Which lies on the given circle ⇒ locus is a circle