The equation of director circle of hyperbola is x236−y225=1 is
A
x2+y2=4
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B
x2+y2=11
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C
x2−y2=4
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D
x2+y2=61
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Solution
The correct option is Ax2+y2=11 The Director circle of a hyperbola is defined as the locus of the point of intersection of two perpendicular tangents to the hyperbola. For any standard hyperbola x2a2−y2b2=1,
The equation of Director circle is given by x2+y2=a2−b2
Here the given hyperbola is x236−y225=1,
Here a=6 and b=5
So equation of the director circle will be x2+y2=(6)2−(5)2